I also preserved the capture group around the whitespace, if you don't want this then remove the brackets as already described above. If you want to match multiple whitespaces then see my comments above. Note as I have already pointed out that the negative lookahead ?! will not match when wordB is followed by a single whitespace and wordc. I replaced wordc with \swordc since that is more explicit. The only difference is that not the regex matches whitespace OR. Preserving your original regex you can use: wordA((?:\s| )*)wordB(?!(?:\s| )wordc) Hello the problem is not the expression but the HTML out put that are not considered as whitespace. Are you capturing the whitespace to a group for a reason? If not you could just remove the brackets, i.e. (\s*) - the brackets indicate a capturing group. You may want to consider + if you want at least one space. * will match 0 or more spaces so it will match wordAwordB. Of course, if you do want to match lines with wordc after wordB then you shouldn't use a negative lookahead. If you want to match against more than one space before wordc you can use (?!\s*wordc) for 0 or more spaces or (?!\s*+wordc) for 1 or more spaces depending on what your intention is. You may want to be more precise and use (?!\swordc). Currently you are relying on the space after ?! to match the whitespace. ![]() (?! wordc) is a negative lookahead, so you wont match lines wordA wordB wordc which is assume is intended (and is why the last line is not matched). Note that all matches are replaced no matter how many spaces. Here are some example matches and the associated replacement output: Note the single space between ?! and wordc which means that wordA wordB wordc will not match, but wordA wordB wordc will. This means match wordA followed by 0 or more spaces followed by wordB, but do not match if followed by wordc. Assuming that it is doing what you want it to. Note that regular expressions are case-sensitive and that \S is different from \s.Your regex should work 'as-is'. In whitespaceMatcher2, we use the character \s to identify single whitespace which returns true for the string " ". Then, we print whitespaceMatcher1 that outputs true, meaning that the pattern matches and finds whitespaces. In the below program, we use Pattern.matches() to check for the whitespaces using the regex \s+ and then the string with three whitespaces. The difference between these regex characters is that \s represents a single whitespace character while \s+ represents multiple whitespaces in a string. The most common regex character to find whitespaces are \s and \s+. The method matches() takes two arguments: the first is the regular expression, and the second is the string we want to match. To use the regex search pattern and see if the given string matches the regex, we use the static method matches() of the class Pattern. Furthermore, you can find the Troubleshooting Login Issues section which can answer your unresolved problems and equip you with a lot of relevant information. Find Whitespace Using Regular Expressions in Java Regex Find All Whitespace LoginAsk is here to help you access Regex Find All Whitespace quickly and handle each specific case you encounter. In the following example, we will see how we can use various regex characters to find whitespaces in a string. Java Binary Search Interactive and RecursiveĪ Regular Expression or regex is a combination of special characters that creates a search pattern that can be used to search for certain characters in Strings. You can use to decode a regular expression into English or to write your own regular expression with Simple Regex Language. ![]()
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |